Wawa Welcome America! July 4th Getaway Sweeps***6 States***-6/6

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https://www.wawa.com/about/promotions/welcome-america
Open to res of: Delaware, Florida, Maryland, New Jersey, Pennsylvania, and Virginia

• A random drawing will be conducted for each of the states of Delaware, Maryland, New Jersey, Pennsylvania, and Virginia from among all eligible entries received for the specified state to award one (1) prize per state. Each prize will consist of a trip for up to four (4) people to travel to Philadelphia, PA, and attend the Wawa Welcome America! 4th of July Concert and Fireworks on July 4, 2017. The prize includes a Wawa Gift Card valued at Two Hundred Fifty Dollars ($250) to be used for gas and transportation expenses; accommodations in one (1) hotel room at the official hotel (TBD) of the Wawa Welcome America! Festival for the nights of July 3, 2017 and July 4, 2017; and reserved seating at the Wawa Welcome America! Concert and Fireworks on July 4, 2017. Approximate Retail Value (“ARV”) is One Thousand Dollars ($1,000) per prize.

• A random drawing for the state of Florida will be conducted from among all eligible entries received from Entrants residing in the state of Florida to award the following prize: a trip for up to four (4) people to travel to Philadelphia, PA, and attend the Wawa Welcome America! 4th of July Concert and Fireworks on July 4, 2017. The prize consists of round trip coach air travel for four (4) people to Philadelphia, PA, from a major commercial airport near winner's residence (as determined by Sponsor); accommodations in one hotel room at the official hotel (TBD) of the Wawa Welcome America! Festival for the nights of July 3, 2017 and July 4, 2017; and reserved seating at the Wawa Welcome America! Concert and Fireworks on July 4, 2017. The ARV of the Florida prize is Two Thousand Two Hundred Fifty Dollars ($2,250).

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Ends soon...